Exergy and Anergy
1 / 10
In a heat exchanger, hot water at 400 K loses 2000 kJ of heat to cold water, with surroundings at 300 K. If the process is irreversible, the exergy destruction is minimum when:
The entropy generation is zero
The heat transfer occurs at 300 K
The cold water temperature is 400 K
The anergy is maximum
Exergy destruction is minimized when the process is reversible, i.e., when entropy generation (S_gen) is zero. Per Gouy-Stodola theorem, X_destroyed = T₀ × S_gen, so S_gen = 0 implies no exergy destruction.
2 / 10
The exergy of a stream of ideal gas flowing at steady state is given by:
X = ṁ (h – hâ‚€) + Tâ‚€(s – sâ‚€)
X = ṁ [(h – hâ‚€) – Tâ‚€(s – sâ‚€)]
X = ṁ (u – uâ‚€) – Tâ‚€(s – sâ‚€)
X = ṁ [(h – hâ‚€) + Tâ‚€(s – sâ‚€)]
For a steady-flow system, the specific flow exergy is x = (h – hâ‚€) – Tâ‚€(s – sâ‚€), where h and s are the enthalpy and entropy of the stream, and hâ‚€, sâ‚€ are at the dead state. For mass flow rate ṁ, X = ṁ x
3 / 10
A system receives 500 kJ of heat at 400 K from a source, with surroundings at 300 K. The maximum work that can be obtained is:
500 kJ
375 kJ
125 kJ
250 kJ
 Maximum work (exergy) = Q [1 – (Tâ‚€/T)] = 500 [1 – (300/400)] = 500 × 0.25 = 125 kJ, where Tâ‚€ = 300 K and T = 400 K.
4 / 10
For an irreversible process, the exergy destruction is:
Always zero
Always negative
Always positive
Equal to the anergy
 Exergy destruction occurs due to irreversibilities (e.g., friction, heat transfer across finite temperature differences) and is always positive, as per Gouy-Stodola theorem: X_destroyed = T₀ × S_gen, where S_gen > 0.
5 / 10
The second law efficiency of a process is defined as:
The ratio of actual work to reversible work
The ratio of exergy output to exergy input
The ratio of heat input to work output
The ratio of anergy to total energy
 Second law efficiency (η₂) is the ratio of the exergy recovered (or useful exergy output) to the exergy supplied, reflecting how effectively a process utilizes available work.
6 / 10
A heat reservoir at 500 K transfers 1000 kJ of heat to the surroundings at 300 K. The exergy loss due to this process is:
400 kJ
600 kJ
200 kJ
1000 kJ
 Exergy loss = Q [1 – (Tâ‚€/T)] = 1000 [1 – (300/500)] = 1000 × 0.4 = 400 kJ, where Tâ‚€ = 300 K is the surroundings temperature and T = 500 K is the reservoir temperature.
7 / 10
For a closed system, the exergy (X) is given by:
X = U + Pâ‚€V – Tâ‚€S
X = (U – Uâ‚€) + Pâ‚€(V – Vâ‚€) – Tâ‚€(S – Sâ‚€)
X = H – Tâ‚€S
X = (H – Hâ‚€) – Tâ‚€(S – Sâ‚€)
 The exergy of a closed system is X = (U – Uâ‚€) + Pâ‚€(V – Vâ‚€) – Tâ‚€(S – Sâ‚€), where U, V, S are the system’s internal energy, volume, and entropy, and Uâ‚€, Vâ‚€, Sâ‚€ are the corresponding values at the dead state (Pâ‚€, Tâ‚€).
8 / 10
The exergy of a system in thermodynamic equilibrium with its surroundings is:
Maximum
Minimum
Zero
Infinite
 At the dead state (equilibrium with the surroundings), the system has no potential to do work, so its exergy is zero.
9 / 10
Anergy is best described as:
The portion of energy that can be converted into useful work
The total internal energy of a system
The entropy generated during an irreversible process
The portion of energy that cannot be converted into useful work
Anergy is the part of the total energy that is unavailable for conversion into useful work, often associated with losses due to irreversibilities or heat transfer to the surroundings.
10 / 10
Exergy is defined as:
The total energy of a system
The maximum useful work that can be obtained from a system
The energy that is unavailable for doing work
The heat transfer during a reversible process
 Exergy is the maximum theoretical useful work (shaft work or electrical work) obtainable from a system as it reaches equilibrium with its surroundings (dead state).
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